The value of China’ export of automobile and part i approximately F of X equal 1. 8208 to the E to the 0. 3387. Ak her ak equal ze

The value of China’ export of automobile and part i approximately F of X equal 1. 8208 to the E to the 0. 3387. Ak her ak equal zero correpond in 1998 and what year did will the oxford reach 5. 3 billion

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  1. In the year 2002 the exports of Chinese’s automobile parts will $5.3 billion.

    Explain the term exponential function?

    • The formula for an exponential function is f (x) = a^e, where x is a variable and an is a constant that serves as the function’s base and must be bigger than 0.
    • The transcendental number e, or roughly 2.71828, is the most often used exponential function basis.
    The exponential function for the given export of Chinese’s automobile parts is-
    5.3 = 1.8208 e^0.3387x
    5.3/1.8208 = e^0.3387x
    Taking ln both sides-
    ln(5.3/1.8208) = ln e^0.3387x
    ln(5.3/1.8208) = 0.3387x
    Further simplifying
    x = ln(5.3/1.8208)/0.3387
    x =  3.15
    x ≈ 3 year ad some months
    Add 3 years to 1998 to get the required year.
    Year = 1998 + 3
    Year = 2001 and months
    Year = 2002
    Thus, in the year 2002 the exports of Chinese’s automobile parts will $5.3 billion.
    To know more about the exponential function, here
    #SPJ4
    The correct question is-
    The value of China’s exports of automobiles and parts (in billions of dollars) is approximately f(x) = 1.8208e^.3387x, where x = 0 corresponds to 1998.
    In what year did/will the exports reach $5.3 billion?

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