Question

The two lines y = 2x + 8 and y = 2x – 12 intersect the x-axis at the P and Q.
Work out the distance PQ.

1. Giakhanh
PQ = 10 units
Step-by-step explanation:
to find where the lines cross the x- axis let y = 0 and solve for x , that is
2x + 8 = 0 ( subtract 8 from both sides )
2x = – 8 ( divide both sides by 2 )
x = – 4 ← point P
and
2x – 12 = 0 ( add 12 to both sides )
2x = 12 ( divide both sides by 2 )
x = 6 ← point Q
the lines cross the x- axis at x = – 4 and x = 6
using the absolute value of the difference , then
PQ = | – 4 – 6 | = | – 10 | = 10 units
or
PQ = | 6 – (- 4) | = | 6 + 4 | = | 10 | = 10 units

2. diemkieu
Answer: Step-by-step explanation:

## Find the point P

Given expression
y = 2x + 8
Substitute 0 for the y value to find the x value
This is the definition of x-intercepts
(0) = 2x + 8
Subtract 8 on both sides
0 – 8 = 2x + 8 – 8
-8 = 2x
Divide 2 on both sides
-8 / 2 = 2x / 2
x = -4 ## Find the point Q

Given expression
y = 2x – 12
Substitute 0 for the y value to find the x value
(0) = 2x – 12
0 + 12 = 2x – 12 + 12
12 = 2x
Divide 2 on both sides
12 / 2 = 2x / 2
x = 6 ## Find the distance between PQ

Given information  Substitute values into the distance formula  Simplify values in the parenthesis Simplify values in the radical sign  Hope this helps!! 🙂
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