Question The two lines y = 2x + 8 and y = 2x – 12 intersect the x-axis at the P and Q. Work out the distance PQ.

Answer: PQ = 10 units Step-by-step explanation: to find where the lines cross the x- axis let y = 0 and solve for x , that is 2x + 8 = 0 ( subtract 8 from both sides ) 2x = – 8 ( divide both sides by 2 ) x = – 4 ← point P and 2x – 12 = 0 ( add 12 to both sides ) 2x = 12 ( divide both sides by 2 ) x = 6 ← point Q the lines cross the x- axis at x = – 4 and x = 6 using the absolute value of the difference , then PQ = | – 4 – 6 | = | – 10 | = 10 units or PQ = | 6 – (- 4) | = | 6 + 4 | = | 10 | = 10 units Reply

Answer: Step-by-step explanation: Find the point P Given expression y = 2x + 8 Substitute 0 for the y value to find the x value This is the definition of x-intercepts (0) = 2x + 8 Subtract 8 on both sides 0 – 8 = 2x + 8 – 8 -8 = 2x Divide 2 on both sides -8 / 2 = 2x / 2 x = -4 Find the point Q Given expression y = 2x – 12 Substitute 0 for the y value to find the x value (0) = 2x – 12 Add 12 on both sides 0 + 12 = 2x – 12 + 12 12 = 2x Divide 2 on both sides 12 / 2 = 2x / 2 x = 6 Find the distance between PQ Given information Substitute values into the distance formula Simplify values in the parenthesis Simplify values in the radical sign Hope this helps!! 🙂 Please let me know if you have any questions Reply

Answer:Step-by-step explanation:Answer:Step-by-step explanation:## Find the point P

Given expressionSubstitute 0 for the y value to find the x valueThis is the definition of x-interceptsSubtract 8 on both sidesDivide 2 on both sides## Find the point Q

Given expressionSubstitute 0 for the y value to find the x valueAdd 12 on both sidesDivide 2 on both sides## Find the distance between PQ

Given informationSubstitute values into the distance formulaSimplify values in the parenthesisSimplify values in the radical sign