Question The surface areas of two cubes have a ratio of 49to 81. What is the ratio of the edge lengths of the two cubes

Answer: Btw, this isn’t my answer someone else answered this same question, but here’s the credits to amanksingh010 Step-by-step explanation: Ratio of their volumes => 343:729 Step-by-step explanation: Let “a” be the side of 1st cube, and “b” be the side of 2nd cube. Given, ratio of surface areas of two cubes are 49:81 Hence, 6a^2/6b^2 = 49/81 [Surface area of a cube=6(side)^2] 6 will cancel out, i.e., => a^2/b^2 = 49/81 => (a/b)^2 = 49/81 => a/b = 7/9 [49 is square of 7 and 81 is square of 9] So, we got the side of 1st cube ‘a’ = 7 and, side of 2nd cube ‘b’ = 9 Ratio of their volumes => a^3/b^3 = 7/9 [Volume of a cube = (side)^3] (a/b)^3 = 7/9 => (7/9)^3 => 343/729 Ratio => 343:729 Log in to Reply

Answer:Btw, this isn’t my answer someone else answered this same question, but here’s the credits to amanksingh010

Step-by-step explanation:Ratio of their volumes => 343:729

Step-by-step explanation:

Let “a” be the side of 1st cube, and

“b” be the side of 2nd cube.

Given, ratio of surface areas of two cubes are 49:81

Hence, 6a^2/6b^2 = 49/81 [Surface area of a cube=6(side)^2]

6 will cancel out, i.e., => a^2/b^2 = 49/81

=> (a/b)^2 = 49/81

=> a/b = 7/9 [49 is square of 7 and 81 is square of 9]

So, we got the side of 1st cube ‘a’ = 7 and,

side of 2nd cube ‘b’ = 9

Ratio of their volumes =>

a^3/b^3 = 7/9 [Volume of a cube = (side)^3]

(a/b)^3 = 7/9 => (7/9)^3 => 343/729

Ratio => 343:729

Answer:it is 3 to 4

Step-by-step explanation:

This is correct