Question The surface areas of two cubes have a ratio of 49to 81. What is the ratio of the edge lengths of the two cubes
Answer: Btw, this isn’t my answer someone else answered this same question, but here’s the credits to amanksingh010 Step-by-step explanation: Ratio of their volumes => 343:729 Step-by-step explanation: Let “a” be the side of 1st cube, and “b” be the side of 2nd cube. Given, ratio of surface areas of two cubes are 49:81 Hence, 6a^2/6b^2 = 49/81 [Surface area of a cube=6(side)^2] 6 will cancel out, i.e., => a^2/b^2 = 49/81 => (a/b)^2 = 49/81 => a/b = 7/9 [49 is square of 7 and 81 is square of 9] So, we got the side of 1st cube ‘a’ = 7 and, side of 2nd cube ‘b’ = 9 Ratio of their volumes => a^3/b^3 = 7/9 [Volume of a cube = (side)^3] (a/b)^3 = 7/9 => (7/9)^3 => 343/729 Ratio => 343:729 Log in to Reply
Answer:
Btw, this isn’t my answer someone else answered this same question, but here’s the credits to amanksingh010
Step-by-step explanation:
Ratio of their volumes => 343:729
Step-by-step explanation:
Let “a” be the side of 1st cube, and
“b” be the side of 2nd cube.
Given, ratio of surface areas of two cubes are 49:81
Hence, 6a^2/6b^2 = 49/81 [Surface area of a cube=6(side)^2]
6 will cancel out, i.e., => a^2/b^2 = 49/81
=> (a/b)^2 = 49/81
=> a/b = 7/9 [49 is square of 7 and 81 is square of 9]
So, we got the side of 1st cube ‘a’ = 7 and,
side of 2nd cube ‘b’ = 9
Ratio of their volumes =>
a^3/b^3 = 7/9 [Volume of a cube = (side)^3]
(a/b)^3 = 7/9 => (7/9)^3 => 343/729
Ratio => 343:729
Answer:it is 3 to 4
Step-by-step explanation:
This is correct