Question

The surface area S of a right pyramid is given by S=1/2P1+B, where P is the perimeter of the base, 1 is the slant height, and B is the area of the base. Solve for 1

Please help​

Answers

  1. The expression for the slant height is l = 2(S-B)/P

    Subject of formula

    The subject of formula is a way of representing a variable in  terms of other variables.
    Given the formula for calculating the surface area as;
    S=1/2Pl + B
    We are to find the value of the slant height.
    Subtract B from both sides
    S – B = 1/2Pl + B – B
    S – B = 1/2Pl
    Cross multiply
    2(S-B) = Pl
    Divide both sides by P
    2(S-B)/P =Pl/P
    2(S-B)/P = l
    Swap
    l = 2(S-B)/P
    Hence the expression for the slant height is l = 2(S-B)/P
    Learn more on subject of formula here: https://brainly.com/question/657646
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