The sum of two numbers is eighteen. The total of three times the smaller and twice the larger is forty-four. Find the two numbers.
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Answer:
- The numbers are 8 and 10.
Step-by-step explanation:Let the numbers be x and y.The sum of two numbers is eighteen:- x + y = 18
The total of three times the smaller and twice the larger is forty-four:- 3x + 2y = 44
Solve the system by substitution:- x = 18 – y
Substitute x and solve for y:- 3(18 – y) + 2y = 44
- 54- 3y + 2y = 44
- 54 – y = 44
- y = 54 – 44
- y = 10
Find x:- x = 18 – 10
- x = 8