Question The population of a town is increasing by 4.7% each year. If the town has 21,802 people now, how many people will it have in 7 years?

Answer: 1, 104, 539, 727 people. Step-by-step explanation: This will be an exponential function. The equation for such is [tex]f(x) = a(b)^{x}[/tex]. a = initial value, in this case, 21,802. b = multiplier, in this case, 4.7. x = time, in this case, 7. 1. Insert your variables: [tex]f(x) = 21,802(4.70)^{7}[/tex] 2. Solve parenthesis. [tex]4.7^{7} = 50,662.312[/tex] [tex]f(x) = 21,802(50,662.312)[/tex] 3. Solve. [tex](21,802)(50,662.312) = 1,104,539,727.23[/tex] You would round you answer off, since you can’t have 23% of a person, and your answer would be 1, 104, 539, 727 people. Log in to Reply

Answer:1, 104, 539, 727 people.

Step-by-step explanation:This will be an exponential function.

The equation for such is [tex]f(x) = a(b)^{x}[/tex].

a = initial value, in this case, 21,802.

b = multiplier, in this case, 4.7.

x = time, in this case, 7.

1. Insert your variables:

[tex]f(x) = 21,802(4.70)^{7}[/tex]

2. Solve parenthesis.

[tex]4.7^{7} = 50,662.312[/tex]

[tex]f(x) = 21,802(50,662.312)[/tex]

3. Solve.

[tex](21,802)(50,662.312) = 1,104,539,727.23[/tex]

You would round you answer off, since you can’t have 23% of a person, and your answer would be 1, 104, 539, 727 people.

Answer:

Step-by-step explanation:

21,802 × 1.047⁷ ≈ 30,069