Question The points (1, 5) and (0, –2) fall on a particular line. What is its equation in slope-intercept form?

The equation of the line in slope intercept form is y = 7x – 2 How to find the equation of a line? The equation of the line can be solved with the following equation. y = mx + b where m = slope b = y-intercept Therefore, m = -2 – 5 / 0 – 1 = -7 / -1 m = 7 Hence, using (1, 5) y = 7x + b 5 = 7(1) + b 5 – 7 = b b = -2 Therefore, y = 7x – 2 Hence, the equation of the line in slope intercept form is y = 7x – 2 learn more on equation of a line here: https://brainly.com/question/14956513 #SPJ1 Reply

equationof the linein slope intercept form isy = 7x – 2## How to find the equation of a line?

equation of the linecan be solved with the following equation.y = mx + bm = 7y = 7x + bb = -2y = 7x – 2equationof the linein slope intercept form isy = 7x – 2equation of a line here: https://brainly.com/question/14956513