Question

the nth term of a sequence is given by an²+bn where a and b are integers the 2nd term of the sequence is 2 4th term of the sequence is 20. find the 6th term of the sequence

Answers

  1. Answer:

    54

    Step-by-step explanation:

    Tn = an²+bn

    T2 = a2²+2b

    2 = 4a +2b

    Multiply all through by 2

    4 = 8a +4b

    4b = 4-8a

    T4 = a4² + 4b

    20 = 16a +4b

    4b = 20-16a

    4-8a = 20-16a

    16a -8a = 20-4

    8a = 16

    a = 16/8 = 2

    4b = 4-8a = 4-8(2) = 4-16 = -12

    b = -12/4 = -3

    T6 = a6² + 6b

    T6 = 2(36) + 6(-3) = 72 -18 = 54

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