Question The least value of the function x^2 + px + q is 3 and this occurs when x = – 2. find the values of p and q

Answer: Hello, p=4 q=7 Step-by-step explanation: The vertex of the parabola is (-2,3) Equation of the parabola is k(x+2)²+3=x²+px+q Let’s identify the coefficients: kx²+4kx+4k+3=x²+px+q so k=1 4*1=p 4*1+3=q Reply

Answer:p=4q=7Step-by-step explanation: