The height of a free falling object is represented by the expression -16t2 + v02 + h0 where v o is the initial velocity of 80 feet

Question

The height of a free falling object is represented by the expression -16t2 + v02 + h0 where v o is the initial velocity of 80 feet per second. And h o is the initial height of 25 feet what is the height of the object at t = 2 seconds ( pls no fake answers )

ThanhThu · Answer

Answer: 45 feet  Explain: don’t really have one I do math in my head so I just knew

ThanhThu · Answer

Answer:    The height of the object after 3 seconds is 45 feets.    Step-by-step explanation:    The height of an object thrown into the air with an initial upward velocity of 63 feet per second is given as        Where, h(t) is height of the object in feet and t is the time in seconds.    We have to find the height of the object after 3 seconds. So, substitute t=3.                    Therefore height of the object after 3 seconds is 45 feets.

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