The graph below depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15.

Given : population mean (N) = 100 population stal dov ( 6) = 15 formula : x = pt ( Z * 6 ) P ( 2 7 ? ) = 0’65 Refer to standard normal table lZ table looking up for Z-score corresponding to area 0 65 to the right of the normal curve to find the I-score P LZ > – D : 39 ) = 6.65 2 = – 0:39 DX = 100 + ( – 0 39 x 16 ) = loot – 5:65 2 94:15 Rounded to one decimal place X = 94 . 2

Given : population mean (N) = 100

population stal dov ( 6) = 15

formula : x = pt ( Z * 6 )

P ( 2 7 ? ) = 0’65

Refer to standard normal table lZ table

looking up for Z-score corresponding to

area

0 65 to the right of

the

normal

curve to find the I-score

P LZ > – D : 39 ) = 6.65

2 = – 0:39

DX = 100 + ( – 0 39 x 16 )

= loot – 5:65

2 94:15

Rounded to one decimal place

X = 94 . 2