Question The edges of a cube increase at a rate of 3 cm/s. How fast is the volume changing when the length of each edge is 40 cm?

Answer: 14400 cm³/s Step-by-step explanation: Find the rate of change of volume in terms of edge length, and evaluate the expression for the given conditions. Rate of change of volume V = s³ . . . . volume in terms of edge length (s) dV/dt = 3s²·ds/dt . . . . . . derivative of volume with respect to time For the given values of s and ds/dt, this is … dV/dt = 3(40 cm)²(3 cm/s) = 14400 cm³/s Log in to Reply

Answer:Step-by-step explanation:rate of change of volumein terms ofedge length, andevaluatethe expression for thegivenconditions.## Rate of change of volume

dV/dt =3(40 cm)²(3 cm/s) =14400 cm³/s