The drama club was selling tickets to the school play. Adult tickets cost $8.00 each, and student tickets cost $5.00 each.

The drama club was selling tickets
to the school play. Adult tickets
cost $8.00 each, and student
tickets cost $5.00 each. The little
theater holds 142 people and was
sold out for both Friday and
Saturday. The total sales for the
two days was $1,948.00.
1. How many adult tickets were
sold out over the two days?
2. How many student tickets were
sold out over the two days?

0 thoughts on “The drama club was selling tickets to the school play. Adult tickets cost $8.00 each, and student tickets cost $5.00 each.”

  1. Answer:

    108 student tickets, and 176 adult tickets  were sold

    Step-by-step explanation:

    Adult ticket $8  Call the number of adult tickets sold “a”

    Student ticket $5  Call the number of student tickets sold “s”

    Since we are talking about TWO consecutive days of sold out seats, the total number of seats sold were 2* 142 = 284

    Then we create two different equations with the information given:

    a + s = 284

    8 * a + 5 * s = 1948

    we can solve for s in the first equation as follows: s = 284 – a

    and use it in the second equation

    8 a + 5 (284 – a) = 1948

    8 a + 1420 – 5 a = 1948

    combining

    3 a = 528

    a = 528/3

    a = 176

    we find the number of student tickets using this answer in the substitution equation we used:

    s – 284 – 176 = 108

    Therefore 108 student tickets, and 176 adult tickets  were sold.

    Reply

Leave a Comment