The brakes applied to a car

produce an acceleration of 6 m s-²

the opposite direction to the motion. If

the car takes 2 seconds to stop after the

application of brakes, calculate the

distance it travels during this time.

produce an acceleration of 6 m s-²

the opposite direction to the motion. If

the car takes 2 seconds to stop after the

application of brakes, calculate the

distance it travels during this time.

Explanation:[tex]from \: newton \: first \: equation \\ V = U + at \\ 0 = U + ( – 6 \times 2) \\ U = 12 \: m {s}^{ – 1} \\ from \: newtons \: third \: equation \\ {V}^{2} = {U}^{2} + 2aS \\ 0 = {12}^{2} + (2 \times – 12 \times \: S ) \\ 144 = 24S \\S = 6 \: m [/tex]