The bottom of a box has a surface area of 31.4cm2. The mass of the box is 47.1 kilograms. Acceleration due to gravity at s3a level is 9.80 m/s2. What pressure is exerted by the box where it rests ?

Answer:

The correct answer to the physics problem in pressure given above would be 1.5 N.

First, I converted the cm^2 to m^ 2 (31.4 cm^2 = .00314 m^2).

Then I computed for the force (F= mg = (47.1kg)(9.8m/s^2) = 461.58 N)

Consequently, I used the equation of pressure (P = Force/Area).

Answer:The correct answer to the physics problem in pressure given above would be 1.5 N.

First, I converted the cm^2 to m^ 2 (31.4 cm^2 = .00314 m^2).

Then I computed for the force (F= mg = (47.1kg)(9.8m/s^2) = 461.58 N)

Consequently, I used the equation of pressure (P = Force/Area).

P = 461.58 N / .00314 m^2

P = 1.47 or 1.5 N

Explanation: