The area of the hardscape is 3x^2 + 13x + 4. what is the length and width of the hardscape
Answer:
[tex](3x+1)[/tex]
[tex](x+4)[/tex]
Step-by-step explanation:
Assuming that the given surface is two-dimensional, one can simply factor the given polynomial to find the dimensions of the surface.
[tex]3x^2 + 13x + 4[/tex]
Just by looking at the polynomial, it is fairly obvious that the factors are;
[tex](3x+1)(x+4)[/tex]
One can check this by distributing, multiply every term in one of the parenthesis by every term in the other. Then combine like terms,
[tex]3x^2 + 12x + x + 4\\\\3x^2 + 13x + 4[/tex]
Without further information, it is impossible to determine which is the length, and which is the width, one just knows that the dimensions of the surface are;
Answer:
[tex](3x+1)[/tex]
[tex](x+4)[/tex]
Step-by-step explanation:
Assuming that the given surface is two-dimensional, one can simply factor the given polynomial to find the dimensions of the surface.
[tex]3x^2 + 13x + 4[/tex]
Just by looking at the polynomial, it is fairly obvious that the factors are;
[tex](3x+1)(x+4)[/tex]
One can check this by distributing, multiply every term in one of the parenthesis by every term in the other. Then combine like terms,
[tex]3x^2 + 12x + x + 4\\\\3x^2 + 13x + 4[/tex]
Without further information, it is impossible to determine which is the length, and which is the width, one just knows that the dimensions of the surface are;
[tex](3x+1)\\\\(x+4)[/tex]