Question The area of a rectangle is with length x 3. using synthetic division, what is the width of the rectangle?

The width of the rectangle using synthetic division is; 5x² + 4x – 6. What is the width of the rectangle whose area is 5x³+19x²+6x-18? From the task content; the width of the rectangle whose area and length are as given can be evaluated as follows; Area = Length × width Hence, width = Area/length. Thus, given an area of (5x³ + 19x² + 6x – 18) and a length of (x + 3), to find the width, we have width = (5x³ + 19x² + 6x – 18) / (x + 3) Through the coefficients of the polynomial, we can apply synthetic division to find the quotient as shown below. 5 19 6 -18 | -3 -15 -12 18 _____________ 5 4 -6 0 Thus, the given values below the line are the coefficients of the width. So, we have the rectangle’s width as (5x² + 4x – 6) units. Read more on area of a rectangle brainly.com/question/20693059 #SPJ4 The complete question is – The area of a rectangle is 5×3+19×2+6x-18 with length x + 3. Using synthetic division, what is the width of the rectangle? Reply

width of the rectangleusing synthetic division is;5x² + 4x – 6.What is the width of the rectangle whose area is 5x³+19x²+6x-18?Area = Length × widthwidth = Area/length.(5x² + 4x – 6) units.area of a rectanglebrainly.com/question/20693059#SPJ4The complete question is –