Suppose there is a sample of xenon in a rectangular container. The gas exerts a total force of 4.47 N perpendicular to one of the container walls, whose dimensions are 0.125 m by 0.209 m . Calculate the pressure of the sample.

Answer:

The pressure is [tex]P=170.61 Nm^{-2}[/tex].

Explanation:

Calculate the area of the rectangular container.

A=LB

Here, L is the length and B is the breadth.

Put L=0.125 m and B= 0.209 m.

A=(0.125)(0.209)

[tex]A = 0.0262 m^{2}[/tex]

The expression for the pressure in terms of area and force is as follows;

[tex]P=\frac{F}{A}[/tex]

Here, P is the pressure and F is the force.

Put [tex]A = 0.0262 m^{2}[/tex] and F= 4.47 N.

[tex]P=\frac{4.47}{0.0262}[/tex]

[tex]P=170.61 Nm^{-2}[/tex]

Therefore, the pressure of the given sample is [tex]P=170.61 Nm^{-2}[/tex].

Answer:The pressure is[tex]P=170.61 Nm^{-2}[/tex].Explanation:Calculate the area of the rectangular container.A=LBHere, L is the length and B is the breadth.Put L=0.125 m and B= 0.209 m.

A=(0.125)(0.209)

[tex]A = 0.0262 m^{2}[/tex]

The expression for the pressure in terms of area and force is as follows;[tex]P=\frac{F}{A}[/tex]

Here, P is the pressure and F is the force.

Put [tex]A = 0.0262 m^{2}[/tex] and F= 4.47 N.

[tex]P=\frac{4.47}{0.0262}[/tex]

[tex]P=170.61 Nm^{-2}[/tex]

Therefore, the pressure of the given sample is[tex]P=170.61 Nm^{-2}[/tex].