suppose x is a normal random variable with and find p(x > 105.0). a) 0.9993 b) 0.9994 c) 0.9995 d) 0.0007 e) 0.0006 f) none of the above.

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huyenthanh · Answer

The value of the probability p(x > 105.0) for the given  normal random variable  is found as 0.6915.  Explain the term normal random variable?   A randomly distributed variable with a mean of 0 and a standard deviation of 1 is referred to as a standard random variable.   The letter Z will always stand in for it.   regularly distributed random variable, also known as a with standard deviation, is a continuous random variable which probabilities are defined by the normal distribution of mean and  standard deviation.    For the stated question -  The formula for the z score -  z = (x - μ)/σ  In which,  μ = 140  and σ = 20  Put the values-  z = (150 - 140)/20  z = 0.5  p(x > 105.0) = p(z > 0.5)  p(x > 105.0) = 0.6915    Thus, the value of the  probability  p(x > 105.0) for the given  normal random variable is found as 0.6915.    To know more about the  normal random variable,  here   https://brainly.com/question/28087511   #SPJ4    The complete question is-  suppose x is a normal random variable with μ = 140  and σ = 20 and find p(x > 105.0).

Explain the term normal random variable?

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