Superman, with a mass of 150-Kg, goes into outer space to push a 125000-Kg alien spaceship out of stationary orbit. He uses his super strength and pushes the ship away at a speed of 150-m/s. What is the speed of Superman after his big push

Answer:

125000 m/s.

Explanation:

The superman is pushing the spaceship in universe and we know there is absence of air or other interfering forces so in this case the total momentum will be conserved.

So, we can write

[tex]m_1v_1=m_2v_2[/tex]

Where,

[tex]m_1[/tex] = mass of spaceship

[tex]v_1[/tex] = speed of spaceship

[tex]m_2[/tex] = mass of superman

[tex]v_2[/tex] = speed of superman

Now, putting the values given in the question in the above equation,

150 × 125000 = 150 × [tex]v_2[/tex]

Solving for [tex]v_2[/tex] we get,

[tex]v_2[/tex] = 125000 m/s

Thus the speed of superman after pushing the spaceship will be 125000 m/s.

Answer:125000 m/s.Explanation:The superman is pushing the spaceship in universe and we know there is absence of air or other interfering forces so in this case the total momentum will be conserved.

So, we can write

[tex]m_1v_1=m_2v_2[/tex]

Where,

[tex]m_1[/tex] = mass of spaceship

[tex]v_1[/tex] = speed of spaceship

[tex]m_2[/tex] = mass of superman

[tex]v_2[/tex] = speed of superman

Now, putting the values given in the question in the above equation,

150 × 125000 = 150 × [tex]v_2[/tex]

Solving for [tex]v_2[/tex] we get,

[tex]v_2[/tex] = 125000 m/s

Thus the speed of superman after pushing the spaceship will be

125000 m/s.