Question State the discriminant of 6x^2 – 2x + k, and state for which values of k would result in two different real solutions.Please explain process.

The discriminant of the given equation 6x² – 2x + k as required is; 4 – 24k. The value of k for which the equation will result in two different real solutions is; k < 1/6. What is the discriminant of the given quadratic function? Since the discriminant for the standard form quadratic equation; y = ax² + bx +c is given by the formula; Discriminant, D = b² – 4ac On this note, since; a = 6, b = -2 and c = k. Discriminant, D = (-2)² – (4 × 6 × k). D = 4 – 24k Recall, when discriminant, D > 0; the equation would result in two different real solutions. Therefore; 4 – 24k > 0 -24k > -4 k < 1 / 6. Read more on discriminant; https://brainly.com/question/24308741 #SPJ1 Reply

discriminantof the given equation 6x² – 2x + k as required is; 4 – 24k.valueof k for which the equation will result in two differentreal solutions is; k < 1/6.## What is the discriminant of the given quadratic function?

discriminant, D > 0; the equation would result in two different real solutions.discriminant;