source of sinusoidal electromagnetic waves radiates uniformly in all directions. At a distance of 10.0 m from this source, the amplitude of

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1. Answer:

   [tex]175\ \text{N/C}[/tex]

   Explanation:

   [tex]E_1[/tex] = Initial electric field = 3.5 N/C

   [tex]E_2[/tex] = Final electric field

   [tex]r_1[/tex] = Initial distance = 10 m

   [tex]r_2[/tex] = Final distance = 20 cm

   Electric field is given by

   [tex]E=\sqrt{\dfrac{2P}{\pi r^2c\varepsilon_0}}[/tex]

   So,

   [tex]E\propto \dfrac{1}{r}[/tex]

   [tex]\dfrac{E_2}{E_1}=\dfrac{r_1}{r_2}\\\Rightarrow E_2=E_1\dfrac{r_1}{r_2}\\\Rightarrow E_2=3.5\dfrac{10}{0.2}\\\Rightarrow E_2=175\ \text{N/C}[/tex]

   The electric field amplitude at the required point is [tex]175\ \text{N/C}[/tex].

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