Answer: Your answer is……. x^3 + 2x^2 + 4x + 8=0 Note.. if x=-2 then whole equation is 0 So, (x+2) is one factor. x^3 + 2x^2 + 4x + 8 =x^2(x+2)+4(x+2) (x+2)(x^2+4) Mark my answer as brainlist. pls pls pls Log in to Reply
Answer:
Your answer is…….
x^3 + 2x^2 + 4x + 8=0 Note.. if x=-2 then whole equation is 0
So, (x+2) is one factor.
x^3 + 2x^2 + 4x + 8
=x^2(x+2)+4(x+2)
(x+2)(x^2+4)
Mark my answer as brainlist. pls pls pls