Answer: Your answer is……. x^3 + 2x^2 + 4x + 8=0 Note.. if x=-2 then whole equation is 0 So, (x+2) is one factor. x^3 + 2x^2 + 4x + 8 =x^2(x+2)+4(x+2) (x+2)(x^2+4) Mark my answer as brainlist. pls pls pls Log in to Reply

Answer:Your answer is…….

x^3 + 2x^2 + 4x + 8=0 Note.. if x=-2 then whole equation is 0

So, (x+2) is one factor.

x^3 + 2x^2 + 4x + 8

=x^2(x+2)+4(x+2)

(x+2)(x^2+4)

Mark my answer as brainlist. pls pls pls