Question Solve the following system of equations: x = 40 + 3y 6x + 13y = 550 (5, 55) (10, 70) (70, 10) (100, 20)

(10, 70) Change the top equation to x-3y=40. Then multiply each value in that equation by 6 to make it 6x-18y=240. Then subtract each value. You should be left with -31y = -310, making y=10. Reply

(10, 70)

Change the top equation to x-3y=40. Then multiply each value in that equation by 6 to make it 6x-18y=240. Then subtract each value. You should be left with -31y = -310, making y=10.