Solve for x: 6sin^2x+2sin^2x=1 fir – 90 July 30, 2021 by niczorrrr Solve for x: 6sin^2x+2sin^2x=1 fir – 90<x<90

Answer: Here we have the equation: 6*sin²(x) + 2*sin²(x) = 1 and we want to find a solution in the range: -90° < x < 90° First, we can take the sin²(x) as a common factor to get: 6*sin²(x) + 2*sin²(x) = (6 + 2)*sin²(x) = 1 8*sin²(x) = 1 now we can divide both sides by 8 sin²(x) = 1/8 now we can apply the square root to both sides: √(sin²(x) = √(1/8) sin(x) = √(1/8) Now remember the inverse sine function, Asin(x) such that: Asin( sin(x) ) = sin( Asin(x) ) = x If we apply that to both sides, we get: Asin( sin(x) ) = Asin(√(1/8)) x = Asin(√(1/8)) = 20.7° x = 20.7° Reply

Answer:Here we have the equation:

6*sin²(x) + 2*sin²(x) = 1

and we want to find a solution in the range:

-90° < x < 90°

First, we can take the sin²(x) as a common factor to get:

6*sin²(x) + 2*sin²(x) = (6 + 2)*sin²(x) = 1

8*sin²(x) = 1

now we can divide both sides by 8

sin²(x) = 1/8

now we can apply the square root to both sides:

√(sin²(x) = √(1/8)

sin(x) = √(1/8)

Now remember the inverse sine function, Asin(x)

such that:

Asin( sin(x) ) = sin( Asin(x) ) = x

If we apply that to both sides, we get:

Asin( sin(x) ) = Asin(√(1/8))

x = Asin(√(1/8)) = 20.7°

x = 20.7°