Setting up a Cavendish experiment, mass 1 is 10.0g, and mass 2 is 0.50kg. the center-to-center distance is 0.05m. a. What is the magnitude of the gravitational force of mass 1 on mass 2

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Answer:1.334×10⁻¹⁰ N

Explanation:From Newton’s Law,

F = Gm’m/r²……………. Equation 1

Where F = Gravitational force, m’ = mass 1, m = mass 2, r = center to center distance, G = Universal constant.

Given: m’ = 10 g = 0.01 kg, m = 0.5 kg, r = 0.05 m

Constant: G = 6.67×10⁻¹¹ Nm²/kg²

Substitute into equation 1

F =6.67×10⁻¹¹(0.01)(0.5)/0.05²

F = 1.334×10⁻¹⁰ N.

Hence the the gravitational force = 1.334×10⁻¹⁰ N.