Select the correct answer from each drop-down menu. Timothy purchased a computer for $1,000. The value of the computer depreciates by 20% every year. This situation represents. The rate of growth or decay, r, is equal to. So the value of the computer each year is % of the value in the previous year. It will take years for the value of the computer to reach $512.
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It will take 3 years for the value of the computer of initial value $1000 to reach $512.Given, Timothy purchased a computer for $1,000.The value of the computer depreciates by 20% every year.we have to find the number of years value of computer will take to reach $512.Let, the function representing this situation be,V(t) = AB^twhere, A is the initial value of the computer and B is the depreciating rate.So, V(t) = (1000)(1 – 20/100)^tV(t) = (1000)(0.8)^tNow, the value will be, 512512 = 1000(0.8)^t0.512 = (0.8)^tt = 3So, it will take 3 years for the value of the computer of initial value $1000 to reach $512.Hence, it will take 3 years for the value of the computer of initial value $1000 to reach $512.Learn more about Exponential Functions here https://brainly.com/question/12472697#SPJ4