Question

Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-1, -6),A(−1,−6),A, left parenthesis, minus, 1, comma, minus, 6, right parenthesis, comma B(-1,7)B(−1,7)B, left parenthesis, minus, 1, comma, 7, right parenthesis, C(1, 7)C(1,7)C, left parenthesis, 1, comma, 7, right parenthesis, and D(1, -6)D(1,−6)D, left parenthesis, 1, comma, minus, 6, right parenthesis.
Given these coordinates, what is the length of side ABABA, B of this rectangle?

Answers

  1. The length of side AB of this rectangle is 13 units

    How to determine the length of side AB of this rectangle?

    From the question, the coordinates of the rectangle are
    A (-1, -6), B (-1,7), C (1, 7) and D(1,−6).
    The length of side AB of this rectangle is calculated using
    AB = √(x2 – x1)^2 + (y2 – y1)^2
    Where
    A (x1, y1) = (-1, -6)
    B (x2, y2) = (-1,7)
    So, we have:
    AB = √(-1 + 1)^2 + (-6 – 7)^2
    Evaluate
    AB = √169
    Evaluate the exponent
    AB = 13
    Hence, the length of side AB of this rectangle is 13 units
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    Complete question
    Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A (-1, -6), B (-1,7), C (1, 7) and D(1,−6).
    Given these coordinates, what is the length of side AB of this rectangle?

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