Your ears are sensitive to differences in pitch, but they are not very sensitive to differences in intensity. You are not capable of detecti

Question

Your ears are sensitive to differences in pitch, but they are not very sensitive to differences in intensity. You are not capable of detecting a difference in sound intensity level of less than 1 dB. By what factor does the sound intensity increase if the sound intensity level increases from 60 dB to 61 dB

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RI SƠ 5 months 2021-08-09T14:38:36+00:00 1 Answers 11 views 0

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    2021-08-09T14:39:48+00:00

    Answer:

    1.29

    Explanation:

    The level of intensity of sound (β) (in decibels, dB) is given by:

    β  =  10log_{10}(\frac{I}{I_0} ), where I = sound intensity in watts per meter squared and I_0 = reference intensity.

    Change in sound intensity level (Δβ) = \beta _2 - \beta _1 = 61 – 60 = 1

    Δβ = 10log_{10}(\frac{I_2}{I_0}) - 10log_{10}(\frac{I_1}{I_0}) = 1

           10log_{10}(\frac{I_2}{I_0})/(\frac{I_1}{I_0}) = 1

           10log_{10}(\frac{I_2}{I_1})   = 1

                   \frac{I_2}{I_1} = 10^{0.1} = 1.29

    Hence, the sound intensity will increase by a factor of 1.29.

         

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