you travel 4.0km east, 4.0km north, then 5.0km at 53.1 degrees north of west in a total of 5 hours. What is the magnitude and direction of y

you travel 4.0km east, 4.0km north, then 5.0km at 53.1 degrees north of west in a total of 5 hours. What is the magnitude and direction of your average velocity

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  1. Answer:

    Explanation:

    We shall convert all the displacement in vector form .

    i and j represents east and north respectively .

    D₁ = 4 i

    D₂ = 4 j

    D₃ = – 5 cos 53.1 i + 5 sin 53.1 j

    = -3i + 4 j

    Total displacement = D₁ + D₂ + D₃

    = 4i + 4 j – 3i + 4 j

    = i + 8j

    magnitude of displacement = √( 1² + 8² )

    = 8.06 km

    velocity = 8.06 / 5

    = 1.61 km / h

    Direction from x axis in anticlockwise direction .

    Tanθ =  8 / 1 = 8

    θ = 83° north of east .

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