You throw a ball straight upward. As it leaves your hand, its speed is 15 m/s. (a) How much time does it take for the ball to reach the top

Question

You throw a ball straight upward. As it leaves your hand, its speed is 15 m/s. (a) How much time does it take for the ball to reach the top of its trajectory? Start from a fundamental principle and show all your work.

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Latifah 4 years 2021-09-04T06:48:04+00:00 2 Answers 4 views 0

Answers ( )

  1. yenoanh
    0
    2021-09-04T06:49:22+00:00
    Reply

    Answer:

    the ball takes 1.53 s to reach the top of its trajectory.

    Explanation:

    given information:

    the speed, v = – 15 m/s (moving upward)

    (a) How much time does it take for the ball to reach the top of its trajectory?

    we know that the speed for the vertical motion is

    v = v₀ – gt, v₀ = 0

    where

    v = speed (m/s)

    g = gravitational force (9.8 m/s²)

    t = time (s)

    thus

    v = – gt

    -15 = – 9.8 t

    t = 15/9.8

     = 1.53 s

    so, the time that is needed by the ball to reach the top its trajectory is 1.53 s

  2. Ben
    0
    2021-09-04T06:49:34+00:00
    Reply

    Answer:

    The ball takes 1.53 seconds to reach its top trajectory

    Explanation:

    The velocity of the ball will keep pushing it upwards until the velocity becomes zero. Therefore, the ball will reach the top of its trajectory when velocity i.e. V=0,

    Fundamental principal of velocity is V = Vo + g*t

    where, V=0  

    Vo = 15 m/s

    g = -9.8 m/s^2 (since ball is going upwards against the gravity)

    t = ?  

    0 = 15 + (-9.8 * t)

    -15 = -9.8t

    -15 / -9.8 = t

    t = 1.53 Seconds

    The ball takes 1.53 seconds to reach its top trajectory

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