You shine unpolarized light with intensity 52.0 W/m2 on an ideal polarizer, and then the light that emerges from this polarizer falls on a s

Question

You shine unpolarized light with intensity 52.0 W/m2 on an ideal polarizer, and then the light that emerges from this polarizer falls on a second ideal polarizer. The light that emerges from the second polarizer has intensity 15.0 W/m2. Find the intensity of the light that emerges from the first polarizer.

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Nem 6 months 2021-08-10T01:08:56+00:00 1 Answers 5 views 0

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    2021-08-10T01:10:01+00:00

    Answer:

    The intensity of light from the first polarizer  is I_1  =  26 W/m^2

    Explanation:

      The intensity of the unpolarized light is  I_o  =  52.0 \ W/m^2

       

    Generally the intensity of light that emerges from the first polarized light is

                I_1  =  \frac{I_o}{2 }

     substituting values

                 I_1  =  \frac{52. 0}{2 }

                 I_1  =  26 W/m^2

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