You put a 3 kg block in the box, so the total mass is now 8 kg, and you launch this heavier box with an initial speed of 4 m/s. How long doe

Question

You put a 3 kg block in the box, so the total mass is now 8 kg, and you launch this heavier box with an initial speed of 4 m/s. How long does it take to stop

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Adela 5 months 2021-09-04T07:30:35+00:00 2 Answers 7 views 0

Answers ( )

    0
    2021-09-04T07:31:42+00:00

    Answer:

    Explanation:

    The box stops at zero speed.

    Final Velocity = 0 ,Initial speed (s)= -4 m/s

    Therefore=  change in velocity =  Vf – Vi.  ( 0 m/s- 4 m/s) =  -4 m/s

    Change in velocity  = -0.4 m/s

    Gravity  g = 9.8 m/s^2

    Mass= 0.8 g

    -4 ms divided by 9.8 ms^2 * (0.8) = 0.51 s

    It takes 0.51 seconds to stop

    0
    2021-09-04T07:32:15+00:00

    Answer:

    0.7 secs

    Explanation:

    In this question, the speed does not change as the mass changes. So we can use

    Δt=Δ∨x/χgμ……………………….equ 1

    To stop, the final speed will be 0

    Therefore,

    Δvx=vf-vt

    Δvx=0-4m/s

    =     -4m/s

    Now substitute the various values in equ 1

    Δt=Δ∨x/χgμ

    Δt=  –4m/s/(9.8m/s∧2) (0.6)

    Δt=0.7 secs

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