You pull a solid nickel ball with a density of 8.91 g/cm3 and a radius of 1.40 cm upward through a fluid at a constant speed of 9.00 cm/s. T

Question

You pull a solid nickel ball with a density of 8.91 g/cm3 and a radius of 1.40 cm upward through a fluid at a constant speed of 9.00 cm/s. The fluid exerts a drag force that is directly proportional to speed, and the proportionality constant is 0.950 kg/s. What is the magnitude of the force (in N) you exert on the ball? (You may ignore the buoyant force.)

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Ngọc Diệp 2 weeks 2021-08-28T17:50:41+00:00 1 Answers 0 views 0

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    2021-08-28T17:52:11+00:00

    Answer:

    P = 1.090\,N

    Explanation:

    The constant speed means that ball is not experimenting acceleration. This elements is modelled by using the following equation of equilibrium:

    \Sigma F = P - W + F_{D}

    \Sigma F = P - \rho \cdot V \cdot g + c\cdot v = 0

    Now, the exerted force is:

    P = \rho \cdot V \cdot g - c\cdot v

    The volume of a sphere is:

    V = \frac{4\cdot \pi}{3}\cdot R^{3}

    V = \frac{4\cdot \pi}{3}\cdot (0.014\,m)^{3}

    V = 1.149\times 10^{-5}\,m^{3}

    Lastly, the force is calculated:

    P = (8910\,\frac{kg}{m^{3}} )\cdot (1.149\cdot 10^{-5}\,m^{3})\cdot (9.81\,\frac{m}{s^{2}} )+(0.950\,\frac{kg}{s})\cdot (0.09\,\frac{m}{s} )

    P = 1.090\,N

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