You obtain a 100 W light bulb and a 50 W light bulb. Instead of connecting them in the normal way, you devise a circuit that places them in

Question

You obtain a 100 W light bulb and a 50 W light bulb. Instead of connecting them in the normal way, you devise a circuit that places them in series across normal household voltage. Which bulb glows more brightly?

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Thành Đạt 2 months 2021-07-24T12:44:23+00:00 1 Answers 2 views 0

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    2021-07-24T12:45:54+00:00

    Answer:

    50W bulb

    Explanation:

    Considering the relationship between power, resistance and voltage, we know that

    R=\frac {v^{2}}{p}

    Where R is resistance, V is voltage across the circuit and P is power

    Considering 100 W power, its resistance will be

    R_{100}=\frac {v^{2}}{100}

    Similarly, resistance of a 50 W power will be

    R_{50}=\frac {v^{2}}{50}

    Clearly, the resistance of 50W is greater than resistance of 100W

    For series connection, power will be given by

    P=I²R

    For 100W bulb, power will be

    P_{100}=I^{2}\frac {v^{2}}{100}

    For 50W bulb, power will be

    P_{50}=I^{2}\frac {v^{2}}{50}

    The current will be the same hence it is clear that power of 50W bulb will be more than power of 100W bulb. Therefore, the 50W bulb has more brightness.

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