You need to produce a set of cylindrical copper wire 3.5 m long that will have a resistance of 0.125 Ω each. What will be the ma

Question

You need to produce a set of cylindrical copper wire 3.5 m long that will have a

resistance of 0.125 Ω each. What will be the mass of each of these wires?

(ρ = 1.72X10-8 Ωm, density of copper = 8.9X103 kg/m3)​

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Ngọc Hoa 6 months 2021-07-27T03:35:52+00:00 1 Answers 97 views 0

Answers ( )

  1. yenoanh
    0
    2021-07-27T03:37:41+00:00
    Reply

    Solution :

    We know, resistance is given by :

    R = \dfrac{\rho l}{A}

    A = \dfrac{\rho l }{R}\\\\A = \dfrac{1.72\times 10^{-8} \times 3.5 }{0.125}\\\\A = 4.816 \times 10^{-7} \ m^2

    Now, we know mass of wire is given by :

    Mass = Density \times Volume\\\\\M = 8.9 \times 10^3 \times 4.816 \times 10^{-7} \times 3.5 kg\\\\M = 0.01500\ kg\\\\M = 15.00\ gram

    Hence, this is the required solution.

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