You measure 20 turtles’ weights, and find they have a mean weight of 45 ounces. Assume the population standard deviation is 11.5 ounces. Bas

Question

You measure 20 turtles’ weights, and find they have a mean weight of 45 ounces. Assume the population standard deviation is 11.5 ounces. Based on this, what is the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight. Give your answer as a decimal, to two places

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3 years 2021-08-25T09:52:26+00:00 1 Answers 24 views 0

1. Answer: the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23

Step-by-step explanation:

Formula for margin of error :

, where z* = Critical z-value.

Given: population standard deviation = 11.5 ounces

Sample size = 20

Z value for 90% confidence level = 1.645

margin of error (E) =

Hence, the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23