You have a special lightbulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.30 A , even for an

Question

You have a special lightbulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.30 A , even for an instant.
What is the largest root-mean-square current you can run through this bulb?

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Linh Đan 3 years 2021-08-25T18:23:45+00:00 1 Answers 5 views 0

Answers ( )

  1. Giakhanh
    0
    2021-08-25T18:25:27+00:00
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    Answer:

    about 0.919 amp

    Explanation:

    I_r_m_s=\frac{I_m_a_x} {\sqrt{2}}\\ I_r_m_s=\frac{1.3}{\sqrt{2}}\\I_r_m_s\approx 0.919 amp

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