You have 26.7 mL of 0.061 mol/L aqueous potassium hydroxide (KOH(aq)) in a conical flask. In a burette you have 0.086 mol/L H2SO4(aq).

Question

You have 26.7 mL of 0.061 mol/L aqueous potassium hydroxide (KOH(aq)) in a conical flask. In a burette
you have 0.086 mol/L H2SO4(aq). If you titrate the two solutions, what volume (mL) of the H2SO4 solution
is required to reach the equivalence point (endpoint)?

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bonexptip 5 months 2021-08-30T10:24:41+00:00 1 Answers 2 views 0

Answers ( )

    0
    2021-08-30T10:26:01+00:00

    Answer:

    9.47 mL

    Explanation:

    The reaction that takes place is:

    • 2KOH + H₂SO₄ → K₂SO₄ + 2H₂O

    First we calculate how many KOH moles reacted, using the given concentration and volume of KOH solution:

    • 0.061 mol/L = 0.061 mmol/mL
    • 0.061 mmol/mL * 26.7 mL = 1.6287 mmol KOH

    Then we convert KOH moles into H₂SO₄ moles, using the stoichiometric coefficients:

    • 1.6287 mmol KOH * \frac{1mmolH_2SO_4}{2mmolKOH} = 0.8144 mmol H₂SO₄

    Finally we calculate the required volume of the H₂SO₄ solution, using the number of moles and given concentration:

    • 0.8144 mmol ÷ 0.086 mmol/mL = 9.47 mL

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