You have 1.2 x 10^25 particles of NiCO3. How many grams are present?

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You have 1.2 x 10^25 particles of NiCO3. How many grams are present?

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Thu Thủy 1 year 2021-09-02T07:51:46+00:00 1 Answers 3 views 0

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    2021-09-02T07:52:58+00:00

    Answer:

    2365.0 g

    Explanation:

    First we convert 1.2 x 10²⁵ particles into moles, using Avogadro’s number:

    • 1.2 x 10²⁵ particles ÷ 6.023×10²³ particles/mol = 19.9 mol

    Then we convert 19.9 moles of NiCO₃ into grams, using the molar mass of NiCO₃:

    • NiCO₃ Molar Mass = 118.702 g/mol
    • 19.9 mol * 118.702 g/mol = 2365.0 g

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