You exert a 138 N push the leftmost of two identical blocks of mass 244 g connected by a spring of stiffness 605 kg/s2. After pushing the bl

Question

You exert a 138 N push the leftmost of two identical blocks of mass 244 g connected by a spring of stiffness 605 kg/s2. After pushing the block a distance 15 cm, you release it; by this time the rightmost block has moved a distance 5 cm. (a) What is the energy in the oscillations between the blocks

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Yến Oanh 2 months 2021-09-05T06:09:56+00:00 1 Answers 1 views 0

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    2021-09-05T06:11:36+00:00

    Answer:

    the energy in the oscillations between the blocks is 3.025 J

    Explanation:

    Given the data in the question;

    Force f = 138 N

    stiffness of spring k = 605 kg/s²

    mass of block = 202 g = 0.202 kg

    pushing the block a distance 15 cm, the rightmost block has moved a distance 5 cm

    i.e

    x₁ = 15 cm

    x₂ = 5cm

    the energy in the oscillations between the blocks will be;

    E_A = E_B = \frac{1}{2}k( Δx )²

    we substitute

    = \frac{1}{2} × k( 15 – 5 )² × 10⁻⁴

    = \frac{1}{2} × 605 × ( 10 )² × 10⁻⁴

    = \frac{1}{2} × 605 × 100 × 10⁻⁴

    = 3.025 J

    Therefore, the energy in the oscillations between the blocks is 3.025 J

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