y^”-2y^’+y=e^x+2xe^(-x) thoa y(0)=1,y^’ (0)=-1

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y^”-2y^’+y=e^x+2xe^(-x) thoa y(0)=1,y^’ (0)=-1

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Ngọc Khuê 5 months 2021-09-02T09:36:00+00:00 1 Answers 3 views 0

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    2021-09-02T09:37:30+00:00

    Answer:

    ummm i dont knoww

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )