y = x2+6x+8 and y = (x+2)(x+4) both define the same quadratic function. Without graphing, identify the x- and y-intercepts of the graph.

Question

y = x2+6x+8 and y = (x+2)(x+4) both define the same quadratic function. Without graphing, identify the x- and y-intercepts of the graph.

Put each of the intercepts in the form of an ordered pair ( . ) ( . ).

You should have three ordered pairs in your answer. Two x-intercepts and one y-intercept. ​

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Diễm Kiều 3 years 2021-08-26T12:55:56+00:00 1 Answers 5 views 0

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  1. Gerda
    0
    2021-08-26T12:57:35+00:00
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    Answer:

    x-int:(-2,0)(-4,0) . y-int:(0,8)

    Step-by-step explanation:

    y = x2+6x+8 and y = (x+2)(x+4)

    x-int:

    x+2=0

    x= -2

    (-2,0)

    x-int:

    x+4=0

    x=-4

    (-4,0)

    y-int: plug 0 for x

    y=(0+2)(0+4)

    y=8

    (0,8)

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )