Wrong answers will be reported. 2cos120°-x sin120°. cos180°= x tan150°

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Wrong answers will be reported.

2cos120°-x sin120°. cos180°= x tan150°

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Gerda 5 months 2021-08-18T01:36:31+00:00 2 Answers 23 views 0

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    0
    2021-08-18T01:37:49+00:00

    Answer:

    (2√3 )/5is he value of x.thank you.

    0
    2021-08-18T01:38:18+00:00

    Answer:

    2cos120°-x sin120°. cos180°= x tan150° \\ 2( -  \frac{1}{2} ) - x( \frac{ \sqrt{3} }{2} ) \times ( - 1) = x{\frac{ \sin( 150°)}{ \cos(150°)}} \\ ( -  \frac{2}{2} ) -  \frac{ \sqrt{3} }{2}x \times ( - 1)  =  x \frac{ \frac{1}{2} }{ -  \frac{ \sqrt{3} }{2} }  \\  - 1 - ( -  \frac{ \sqrt{3} }{2}x) = x( \frac{1}{2}  \times ( -  \frac{2}{ \sqrt{3} } )) \\  - 1 +  \frac{ \sqrt{3} }{2} x = ( - \frac{2}{2 \sqrt{3} } )x \\  - 1 +  \frac{ \sqrt{3} }{2} x = ( -  \frac{1}{ \sqrt{3} } )x \\  - 1 +  \frac{ \sqrt{3} }{2} x =( \frac{ \sqrt{3} }{ \sqrt{3} } )( -  \frac{1}{ \sqrt{3} } )x \\  - 1 +  \frac{ \sqrt{3} }{2} x =  -  \frac{ \sqrt{3} }{3} x \\ 6( - 1 +  \frac{ \sqrt{3} }{2} x) = 6(  -  \frac{ \sqrt{3} }{3} x) \\  - 6 +  \frac{6 \sqrt{3} }{2} x =  -  \frac{6 \sqrt{3} }{3} x \\   - 6 =   \frac{ - 6 \sqrt{3} }{3}x    -  \frac{6 \sqrt{3} }{2} x \\  - 6 =  (- 2 \sqrt{3})x - (3 \sqrt{3})x \\  - 6 =  - 5 \sqrt{3} x \\ x =  \frac{ - 6}{ - 5 \sqrt{3} }  \\ x  =  \frac{  6}{5 \sqrt{3} }  \\ x =  \frac{6}{5 \sqrt{3} }  \times  \frac{ \sqrt{3} }{ \sqrt{3} }  \\ x =  \frac{6 \sqrt{3} }{5 \times 3}  \\ x =  \frac{2\sqrt{3} }{5}

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