write the equation of the line for the following table of values. x. -3 -5 -7 -9 -11

Question

write the equation of the line for the following table of values.

x. -3 -5 -7 -9 -11

y. -16 -26 -36 -46 -56

Plz helppp 35 points:)​

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Thành Đạt 3 years 2021-08-25T18:23:58+00:00 1 Answers 2 views 0

Answers ( )

  1. linhdan
    0
    2021-08-25T18:25:48+00:00
    Reply

    Answer:

    We conclude that the equation of the line is:

    • y = 5x + 1

    Step-by-step explanation:

    The slope-intercept form of the line equation

    y = mx+b

    where

    • m is the slope
    • b is the y-intercept

    Given the data table

    x      -3 -5 -7 -9 -11

    y      -16 -26 -36 -46 -56

    From the table taking two points

    • (-3, -16)
    • (-5, -26)

    Determining the slope between (-3, -16) and (-5, -26)

    \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

    \left(x_1,\:y_1\right)=\left(-3,\:-16\right),\:\left(x_2,\:y_2\right)=\left(-5,\:-26\right)

    m=\frac{-26-\left(-16\right)}{-5-\left(-3\right)}

    m=5

    Thus, the slope of the line is:  m = 5

    substituting m = 5 and (-3, -16) in the slope-intercept form of the line equation  to determine the y-intercept b

    y = mx+b

    -16 = 5(-3) + b

    -16 = -15 + b

    b = -16+15

    b = 1

    Thus, the y-intercept b = 1

    now substituting m = 5 and b = 1 in the slope-intercept form of the line equation

    y = mx+b

    y = 5x + 1

    Therefore, we conclude that the equation of the line is:

    • y = 5x + 1

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