Write the equation of a line perpendicular to y= -5/6x-3 and whose y-intercept is (0,11).

Question

Write the equation of a line perpendicular to y= -5/6x-3 and whose y-intercept is (0,11).

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Thu Hương 4 years 2021-08-14T22:17:50+00:00 1 Answers 14 views 0

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    2021-08-14T22:19:28+00:00

    Answer:

    y=6/5x+11

    Step-by-step explanation:

    Perpendicular lines have the opposite sign and reciprocal of the original line. Since the y-intercept is 11 we know that it is 6/5x+11

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