Write an equation of the parabola in intercept form that passes through (-2, 0.05) with x-intercepts of -7 and -3

Question

Write an equation of the parabola in intercept form that passes through (-2, 0.05) with x-intercepts of -7 and -3

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RuslanHeatt 3 years 2021-07-27T08:37:18+00:00 1 Answers 74 views 0

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  1. thuhuong
    0
    2021-07-27T08:39:13+00:00
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    Important things you need to know:

    1. x intercept = solution of the equation

    2. parabola = the highest power is x²

    3. “passes through” is important because you have the y intercept (it is the c in ax² + bx + c = 0)

    The intercept form is y = a(x-r)(x-s), where r and s are the x intercepts (solutions) of the graph

    Substitite the numbers and values you know:

    y = a(x-r)(x-s)

    0.05 = a(-2-(-7)) × (-2-(-3))

    Then you should find a.

    Rewrite the equation in the form of y = a ( x+7 )( x+3 ) where the value of a is found.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )