Write a balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air.

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Write a balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air.

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Nguyệt Ánh 3 years 2021-07-31T04:51:54+00:00 1 Answers 559 views 0

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  1. ngockhue
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    2021-07-31T04:53:00+00:00
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    Answer: The balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O.

    Explanation:

    When a substance tends to gain oxygen atom in a chemical reaction and loses hydrogen atom then it is called oxidation reaction.

    For example, chemical equation for oxidation of methane is as follows.

    CH_{4} + O_{2} \rightarrow CO_{2} + H_{2}O

    Number of atoms present on reactant side are as follows.

    • C = 1
    • H = 4
    • O = 2

    Number of atoms present on product side are as follows.

    • C = 1
    • H = 2
    • O = 3

    To balance this equation, multiply O_{2} by 2 on reactant side. Also, multiply H_{2}O by 2 on product side. Hence, the equation can be rewritten as follows.

    CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O

    Now, the number of atoms present on reactant side are as follows.

    • C = 1
    • H = 4
    • O = 4

    Number of atoms present on product side are as follows.

    • C = 1
    • H = 4
    • O = 4

    Since, the atoms present on both reactant and product side are equal. Therefore, this equation is now balanced.

    Thus, we can conclude that balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O.

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