wo plastic bowling balls, 1 and 2, are rubbed with cloth until they each carry a uniformly distributed charge of magnitude 0.70 nC . Ball 1

Question

wo plastic bowling balls, 1 and 2, are rubbed with cloth until they each carry a uniformly distributed charge of magnitude 0.70 nC . Ball 1 is negatively charged, and ball 2 is positively charged. The balls are held apart by a 500-mm stick stuck through the holes so that it runs from the center of one ball to the center of the other.

What is the magnitude of the dipole moment of the arrangement?

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Yến Oanh 4 years 2021-07-18T23:29:57+00:00 1 Answers 8 views 0

Answers ( )

  1. ngochoa
    0
    2021-07-18T23:31:23+00:00
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    Answer:

    the  magnitude of the dipole moment is 3.5*10^-11Cm

    Explanation:

    The dipole moment is given by the following formula:

    \mu=qr

    r: distance between the centers of the charges = 500mm

    q: charges of the bowling balls = 0.70nC

    By replacing you obtain:

    \mu=(0.70*10^{-9}C)(500*10^{-4}m)=3.5*10^{-11}Cm

    hence, the magnitude of the dipole moment is 3.5*10^-11Cm

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )