Will mark brainliest! Calculate the final temperature after 15 joules of heat energy is added to 7.3 g of water at 3.2ºC.

Question

Will mark brainliest!
Calculate the final temperature after 15 joules of heat energy is added to 7.3 g of water at 3.2ºC.

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Thanh Hà 2 months 2021-08-22T11:49:57+00:00 1 Answers 0 views 0

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    2021-08-22T11:51:45+00:00

    Answer:

    3.7 °C

    Explanation:

    Step 1: Given and required data

    • Added heat (Q): 15 J
    • Mass of water (m): 7.3 g
    • Initial temperature (T₁): 3.2 °C
    • Specific heat capacity of water (c): 4.184 J/g.°C

    Step 2: Calculate the final temperature (T₂) of the water

    We will use the following expression.

    Q = c ×m ×(T₂ – T₁)

    T₂ = Q / c × m + T₁

    T₂ = 15 J / (4.184 J/g.°C) × 7.3 g + 3.2 °C = 3.7 °C

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